No.1 | 3*x
- 1 - (5*x - (2 - 4*x)) = -11 |
|
This equation apparently is a
linear one. |
No.2 | (x
- 5)*(10 - x) = (3 - x)*(2 + x) + 2*(x + 20) |
|
This equation turns out to be linear, too. |
No.3 | (2*x + 5)^2
+ (3*x + 4)^2 =
(13*x + 2)*(x + 1) + 2*(15 + 14*x) |
No.4 | (2*x+1)^3
+ (x+1)^3 = (2*x+1)^2
* 2*x + (x+2)^3 + x^2 |
No.5 | (6*x
- 9) * (5*x+7) - (4*x+7) *
(3*x - 6) = 429 |
No.6 | 1
= 0 |
No.7 | 0
= 0 |
|
This result is under
consideration. |
No.8 | 2
+ (-1)*x + x^2 = 0 |
No.9 | -2
+ x + x^2 = 0 |
No.10 | x
+ x^2 = 0 |
No.11 | -1
+ x + 2*x^2 = 0 |
|
In all algebra systems term are
ordered like this, in contrary to traditional customs in calculating by
hand. ISAC uses the order above due to the same compellent
technical reasons as algebra systems. |
No.12 | -2
+ x + x^2 = 0 |
No.13 | -8
+ 2*x^2 = 0 |
No.14 | -4
+ x^2 = 0 |
No.15 | 2*x
+ 2*x^2 = 0 |
No.16 | x
+ 2*x^2 = 0 |
No.17 | 3*x
- 1 - (5*x - (2 - 4*x)) = -11 |