2 theory termination = examples:
6 When a function is defined via \isacommand{recdef}, Isabelle tries to prove
7 its termination with the help of the user-supplied measure. All of the above
8 examples are simple enough that Isabelle can prove automatically that the
9 measure of the argument goes down in each recursive call. As a result,
10 $f$@{text".simps"} will contain the defining equations (or variants derived
11 from them) as theorems. For example, look (via \isacommand{thm}) at
12 @{thm[source]sep.simps} and @{thm[source]sep1.simps} to see that they define
13 the same function. What is more, those equations are automatically declared as
16 In general, Isabelle may not be able to prove all termination condition
17 (there is one for each recursive call) automatically. For example,
18 termination of the following artificial function
21 consts f :: "nat\<times>nat \<Rightarrow> nat";
22 recdef f "measure(\<lambda>(x,y). x-y)"
23 "f(x,y) = (if x \<le> y then x else f(x,y+1))";
26 is not proved automatically (although maybe it should be). Isabelle prints a
27 kind of error message showing you what it was unable to prove. You will then
28 have to prove it as a separate lemma before you attempt the definition
29 of your function once more. In our case the required lemma is the obvious one:
32 lemma termi_lem: "\<not> x \<le> y \<Longrightarrow> x - Suc y < x - y";
35 It was not proved automatically because of the special nature of @{text"-"}
36 on @{typ"nat"}. This requires more arithmetic than is tried by default:
43 Because \isacommand{recdef}'s termination prover involves simplification,
44 we include with our second attempt the hint to use @{thm[source]termi_lem} as
45 a simplification rule:
48 consts g :: "nat\<times>nat \<Rightarrow> nat";
49 recdef g "measure(\<lambda>(x,y). x-y)"
50 "g(x,y) = (if x \<le> y then x else g(x,y+1))"
51 (hints recdef_simp: termi_lem)
54 This time everything works fine. Now @{thm[source]g.simps} contains precisely
55 the stated recursion equation for @{term g} and they are simplification
56 rules. Thus we can automatically prove
59 theorem "g(1,0) = g(1,1)";
64 More exciting theorems require induction, which is discussed below.
66 If the termination proof requires a new lemma that is of general use, you can
67 turn it permanently into a simplification rule, in which case the above
68 \isacommand{hint} is not necessary. But our @{thm[source]termi_lem} is not
69 sufficiently general to warrant this distinction.
71 The attentive reader may wonder why we chose to call our function @{term g}
72 rather than @{term f} the second time around. The reason is that, despite
73 the failed termination proof, the definition of @{term f} did not
74 fail, and thus we could not define it a second time. However, all theorems
75 about @{term f}, for example @{thm[source]f.simps}, carry as a precondition
76 the unproved termination condition. Moreover, the theorems
77 @{thm[source]f.simps} are not simplification rules. However, this mechanism
78 allows a delayed proof of termination: instead of proving
79 @{thm[source]termi_lem} up front, we could prove
80 it later on and then use it to remove the preconditions from the theorems
81 about @{term f}. In most cases this is more cumbersome than proving things
83 %FIXME, with one exception: nested recursion.