test/Tools/isac/Knowledge/rateq.sml
branchisac-update-Isa09-2
changeset 37960 ec20007095f2
parent 37926 e6fc98fbcb85
child 37991 028442673981
     1.1 --- /dev/null	Thu Jan 01 00:00:00 1970 +0000
     1.2 +++ b/test/Tools/isac/Knowledge/rateq.sml	Mon Aug 30 14:35:51 2010 +0200
     1.3 @@ -0,0 +1,145 @@
     1.4 +(* RL 09.02 
     1.5 + testexamples for RatEq, equations with fractions
     1.6 +
     1.7 + Compiler.Control.Print.printDepth:=10; (*4 default*)
     1.8 + Compiler.Control.Print.printDepth:=5; (*4 default*)
     1.9 + trace_rewrite:=true;
    1.10 +
    1.11 + use"kbtest/rateq.sml";
    1.12 + *)
    1.13 +"----------- rateq.sml begin--------";
    1.14 +"---------(1/x=5) ---------------------";
    1.15 +"--------- S.68, Bsp.: 40, ((x)/(x - 8) + (x - 8)/(x) = 26/5)---------------------";
    1.16 +
    1.17 +val t = (term_of o the o (parse RatEq.thy)) "(1/b+1/x=1) is_ratequation_in  x";
    1.18 +val SOME(t_, _) = rewrite_set_ RatEq.thy  false RatEq_prls t;
    1.19 +val result = term2str t_;
    1.20 +if result <>  "True"  then raise error "rateq.sml: new behaviour 1:" else ();
    1.21 +
    1.22 +val t = (term_of o the o (parse RatEq.thy)) "(sqrt(x)=1) is_ratequation_in  x";
    1.23 +val SOME(t_, _) = rewrite_set_ RatEq.thy  false RatEq_prls t;
    1.24 +val result = term2str t_;
    1.25 +if result <>  "False"  then raise error "rateq.sml: new behaviour 2:" else ();
    1.26 +
    1.27 +val t = (term_of o the o (parse RatEq.thy)) "(x=-1) is_ratequation_in x";
    1.28 +val SOME(t_,_) = rewrite_set_ RatEq.thy  false RatEq_prls t;
    1.29 +val result = term2str t_;
    1.30 +if result <>  "False"  then raise error "rateq.sml: new behaviour 3:" else ();
    1.31 +
    1.32 +val t = (term_of o the o (parse RatEq.thy)) "(3 + x^^^2 + 1/(x^^^2+3)=1) is_ratequation_in x";
    1.33 +val SOME(t_,_) = rewrite_set_ RatEq.thy  false RatEq_prls t;
    1.34 +val result = term2str t_;
    1.35 +if result <>  "True"  then raise error "rateq.sml: new behaviour 4:" else ();
    1.36 +
    1.37 +val result = match_pbl ["equality (x=1)","solveFor x","solutions L"] 
    1.38 +                (get_pbt ["rational","univariate","equation"]); 
    1.39 +case result of NoMatch' _  => ()  | _ => raise error "rateq.sml: new behaviour: 5";
    1.40 +
    1.41 +val result = match_pbl ["equality (3 + x^^^2 + 1/(x^^^2+3)=1)","solveFor x","solutions L"] 
    1.42 +                (get_pbt ["rational","univariate","equation"]); 
    1.43 +case result of Matches' _  => ()  | _ => raise error "rateq.sml: new behaviour: 6";
    1.44 +
    1.45 +
    1.46 +(*---------rateq---- 23.8.02 ---------------------*)
    1.47 +"---------(1/x=5) ---------------------";
    1.48 +val fmz = ["equality (1/x=5)","solveFor x","solutions L"];
    1.49 +(* refine fmz ["univariate","equation"];
    1.50 +   *)
    1.51 +
    1.52 +val (dI',pI',mI') = ("RatEq.thy",["univariate","equation"],["no_met"]);
    1.53 +val (p,_,f,nxt,_,pt) = CalcTreeTEST [(fmz, (dI',pI',mI'))];
    1.54 +(* val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.55 +   --------------------------------------- Refine_Tacitly*)
    1.56 +(*  nxt = ("Model_Problem",Model_Problem ["rational","univariate","equation"]) *)
    1.57 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.58 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.59 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.60 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.61 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.62 +(* val nxt = ("Subproblem",Subproblem ("RatEq.thy",["univariate","equation"])*)
    1.63 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.64 +(* val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.65 +   --------------------------------------- Refine_Tacitly*)
    1.66 +(*val nxt = ("Model_Problem", Model_Problem ["normalize","polynomial","univariate","equation"])*) 
    1.67 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.68 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.69 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.70 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.71 +(*val nxt = Apply_Method ["PolyEq", "normalize_poly"])*)
    1.72 +
    1.73 +(* get_obj g_fmz pt [2];
    1.74 +   *)
    1.75 +
    1.76 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.77 +(**** assoc_thm': 'all_left' not in 'RatEq.thy' (and parents)*)
    1.78 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.79 +(* val nxt = ("Subproblem",  Subproblem ("PolyEq.thy",["polynomial","univariate","equation"]))*)
    1.80 +
    1.81 +
    1.82 +
    1.83 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.84 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.85 +(*  ("Model_Problem", Model_Problem ["degree_1","polynomial","univariate","equation"])*)
    1.86 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.87 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.88 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.89 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.90 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.91 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.92 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.93 +(* "x = 1 / 5" *)
    1.94 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
    1.95 +if mout2str(f) = "Form' FormKF (~1,EdUndef,0,Nundef,([x = 1 / 5])" then () 
    1.96 +else  raise error "rateq.sml: new behaviour: [x = 1 / 5]";
    1.97 +
    1.98 +
    1.99 +
   1.100 +(*---------((x)/(x - 8) + (x - 8)/(x) = 26/5)---------------------*)
   1.101 +"--------- S.68, Bsp.: 40, ((x)/(x - 8) + (x - 8)/(x) = 26/5)---------------------";
   1.102 +(*EP Schalk_II_p68_n40*)
   1.103 +val fmz = ["equality ((x)/(x - 8) + (x - 8)/(x) = 26/5)","solveFor x","solutions L"];
   1.104 +(* val fmz = ["equality (3+x= 9*x^^^4+((1+2*x)/x^^^2)^^^2 + 6*(x^^^2*((1+2*x)/x^^^2)))",
   1.105 +	   "solveFor x","solutions L"];*)
   1.106 +
   1.107 +(* refine fmz ["univariate","equation"];
   1.108 +*)
   1.109 +
   1.110 +val (dI',pI',mI') = ("RatEq.thy",["univariate","equation"],["no_met"]);
   1.111 +(*val p = e_pos'; 
   1.112 +val c = []; 
   1.113 +val (mI,m) = ("Init_Proof",Init_Proof (fmz, (dI',pI',mI')));
   1.114 +val (p,_,f,nxt,_,pt) = me (mI,m) p c EmptyPtree;*)
   1.115 +val (p,_,f,nxt,_,pt) = CalcTreeTEST [(fmz, (dI',pI',mI'))];
   1.116 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.117 +(* nxt = ("Model_Problem",Model_Problem ["rational","univariate","equation"])*)
   1.118 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.119 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.120 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.121 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.122 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.123 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.124 +(* nxt = ("Subproblem",Subproblem ("RatEq.thy",["univariate","equation"]))*)
   1.125 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.126 +(* nxt = ("Model_Problem", Model_Problem ["normalize","polynomial","univariate","equation"])*)
   1.127 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.128 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.129 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.130 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.131 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.132 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.133 +(* ("Subproblem", Subproblem ("PolyEq.thy",["polynomial","univariate","equation"])) *)
   1.134 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.135 +(* nxt = ("Model_Problem", Model_Problem
   1.136 +     ["abcFormula","degree_2","polynomial","univariate","equation"])*)
   1.137 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.138 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.139 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.140 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.141 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.142 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.143 +val (p,_,f,nxt,_,pt) = me nxt p [1] pt;val (p,_,f,nxt,_,pt) = me nxt p [1] pt;
   1.144 +(* "x = -2, x = 10" *)
   1.145 +if mout2str(f) = "Form' FormKF (~1,EdUndef,0,Nundef,([x = -2, x = 10])" then() 
   1.146 +else  raise error "rateq.sml: new behaviour: [x = -2, x = 10]";
   1.147 +
   1.148 +"----------- rateq.sml end--------";