src/Tools/isac/Knowledge/Partial_Fractions.thy
changeset 59512 e504168e7b01
parent 59505 a1f223658994
child 59513 deb1efba3119
     1.1 --- a/src/Tools/isac/Knowledge/Partial_Fractions.thy	Thu Mar 07 16:50:20 2019 +0100
     1.2 +++ b/src/Tools/isac/Knowledge/Partial_Fractions.thy	Thu Mar 07 17:22:20 2019 +0100
     1.3 @@ -21,11 +21,8 @@
     1.4  subsection \<open>eval_ functions\<close>
     1.5  consts
     1.6    factors_from_solution :: "bool list => real"
     1.7 -  drop_questionmarks    :: "'a => 'a"
     1.8 -(* version for later switch to partial_function
     1.9 -  A                     :: real    \<comment> \<open>PROG redesign (Substitute [A = a, B = b]) pbz ?\<close>
    1.10 -  B                     :: real    \<comment> \<open>PROG redesign (Substitute [A = a, B = b]) pbz ?\<close>
    1.11 -*)
    1.12 +  AA                    :: real
    1.13 +  BB                    :: real
    1.14  
    1.15  text \<open>these might be used for variants of fac_from_sol\<close>
    1.16  ML \<open>
    1.17 @@ -70,56 +67,36 @@
    1.18   | eval_factors_from_solution _ _ _ _ = NONE;
    1.19  \<close>
    1.20  
    1.21 -text \<open>'ansatz' introduces '?Vars' (questionable design); drop these again\<close>
    1.22 -ML \<open>
    1.23 -(*("drop_questionmarks", ("Partial_Fractions.drop_questionmarks", eval_drop_questionmarks ""))*)
    1.24 -fun eval_drop_questionmarks (thmid:string) _
    1.25 -     (t as Const ("Partial_Fractions.drop_questionmarks", _) $ tm) thy =
    1.26 -        if TermC.contains_Var tm
    1.27 -        then
    1.28 -          let
    1.29 -            val tm' = TermC.var2free tm
    1.30 -            in SOME (TermC.mk_thmid thmid (Rule.term_to_string''' thy tm') "",
    1.31 -                 HOLogic.Trueprop $ (TermC.mk_equality (t, tm')))
    1.32 -            end
    1.33 -        else NONE
    1.34 -  | eval_drop_questionmarks _ _ _ _ = NONE;
    1.35 -\<close>
    1.36 -
    1.37 -text \<open>store eval_ functions for calls from Scripts\<close>
    1.38 -setup \<open>KEStore_Elems.add_calcs
    1.39 -  [("drop_questionmarks", ("Partial_Fractions.drop'_questionmarks", eval_drop_questionmarks ""))]\<close>
    1.40 -
    1.41  subsection \<open>'ansatz' for partial fractions\<close>
    1.42  axiomatization where
    1.43 -  ansatz_2nd_order: "n / (a*b) = A/a + B/b" and
    1.44 -  ansatz_3rd_order: "n / (a*b*c) = A/a + B/b + C/c" and
    1.45 -  ansatz_4th_order: "n / (a*b*c*d) = A/a + B/b + C/c + D/d" and
    1.46 +  ansatz_2nd_order: "n / (a*b) = AA/a + BB/b" and
    1.47 +  ansatz_3rd_order: "n / (a*b*c) = AA/a + BB/b + C/c" and
    1.48 +  ansatz_4th_order: "n / (a*b*c*d) = AA/a + BB/b + C/c + D/d" and
    1.49    (*version 1*)
    1.50 -  equival_trans_2nd_order: "(n/(a*b) = A/a + B/b) = (n = A*b + B*a)" and
    1.51 -  equival_trans_3rd_order: "(n/(a*b*c) = A/a + B/b + C/c) = (n = A*b*c + B*a*c + C*a*b)" and
    1.52 -  equival_trans_4th_order: "(n/(a*b*c*d) = A/a + B/b + C/c + D/d) = 
    1.53 -    (n = A*b*c*d + B*a*c*d + C*a*b*d + D*a*b*c)" and
    1.54 +  equival_trans_2nd_order: "(n/(a*b) = AA/a + BB/b) = (n = AA*b + BB*a)" and
    1.55 +  equival_trans_3rd_order: "(n/(a*b*c) = AA/a + BB/b + C/c) = (n = AA*b*c + BB*a*c + C*a*b)" and
    1.56 +  equival_trans_4th_order: "(n/(a*b*c*d) = AA/a + BB/b + C/c + D/d) = 
    1.57 +    (n = AA*b*c*d + BB*a*c*d + C*a*b*d + D*a*b*c)" and
    1.58    (*version 2: not yet used, see partial_fractions.sml*)
    1.59 -  multiply_2nd_order: "(n/x = A/a + B/b) = (a*b*n/x = A*b + B*a)" and
    1.60 -  multiply_3rd_order: "(n/x = A/a + B/b + C/c) = (a*b*c*n/x = A*b*c + B*a*c + C*a*b)" and
    1.61 +  multiply_2nd_order: "(n/x = AA/a + BB/b) = (a*b*n/x = AA*b + BB*a)" and
    1.62 +  multiply_3rd_order: "(n/x = AA/a + BB/b + C/c) = (a*b*c*n/x = AA*b*c + BB*a*c + C*a*b)" and
    1.63    multiply_4th_order: 
    1.64 -    "(n/x = A/a + B/b + C/c + D/d) = (a*b*c*d*n/x = A*b*c*d + B*a*c*d + C*a*b*d + D*a*b*c)"
    1.65 +    "(n/x = AA/a + BB/b + C/c + D/d) = (a*b*c*d*n/x = AA*b*c*d + BB*a*c*d + C*a*b*d + D*a*b*c)"
    1.66  
    1.67  text \<open>Probably the optimal formalization woudl be ...
    1.68  
    1.69 -  multiply_2nd_order: "x = a*b ==> (n/x = A/a + B/b) = (a*b*n/x = A*b + B*a)" and
    1.70 +  multiply_2nd_order: "x = a*b ==> (n/x = AA/a + BB/b) = (a*b*n/x = AA*b + BB*a)" and
    1.71    multiply_3rd_order: "x = a*b*c ==>
    1.72 -    (n/x = A/a + B/b + C/c) = (a*b*c*n/x = A*b*c + B*a*c + C*a*b)" and
    1.73 +    (n/x = AA/a + BB/b + C/c) = (a*b*c*n/x = AA*b*c + BB*a*c + C*a*b)" and
    1.74    multiply_4th_order: "x = a*b*c*d ==>
    1.75 -    (n/x = A/a + B/b + C/c + D/d) = (a*b*c*d*n/x = A*b*c*d + B*a*c*d + C*a*b*d + D*a*b*c)"
    1.76 +    (n/x = AA/a + BB/b + C/c + D/d) = (a*b*c*d*n/x = AA*b*c*d + BB*a*c*d + C*a*b*d + D*a*b*c)"
    1.77  
    1.78  ... because it would allow to start the ansatz as follows
    1.79  (1) 3 / (z * (z - 1 / 4 + -1 / 8 * (1 / z))) = 3 / (z * (z - 1 / 4 + -1 / 8 * (1 / z)))
    1.80  (2) 3 / (z * (z - 1 / 4 + -1 / 8 * (1 / z))) = AA / (z - 1 / 2) + BB / (z - -1 / 4)
    1.81  (3) (z - 1 / 2) * (z - -1 / 4) * 3 / (z * (z - 1 / 4 + -1 / 8 * (1 / z))) = 
    1.82      (z - 1 / 2) * (z - -1 / 4) * AA / (z - 1 / 2) + BB / (z - -1 / 4)
    1.83 -(4) 3 = A * (z - -1 / 4) + B * (z - 1 / 2)
    1.84 +(4) 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)
    1.85  
    1.86  ... (1==>2) ansatz
    1.87      (2==>3) multiply_*
    1.88 @@ -209,21 +186,10 @@
    1.89         Rule.Calc("Rational.get_denominator", eval_get_denominator "#get_denominator"),
    1.90         Rule.Calc("Rational.get_numerator", eval_get_numerator "#get_numerator"),
    1.91         Rule.Calc("Partial_Fractions.factors_from_solution",
    1.92 -         eval_factors_from_solution "#factors_from_solution"),
    1.93 -       Rule.Calc("Partial_Fractions.drop_questionmarks", eval_drop_questionmarks "#drop_?")],
    1.94 +         eval_factors_from_solution "#factors_from_solution")
    1.95 +       ],
    1.96      scr = Rule.EmptyScr};
    1.97  \<close>
    1.98 -ML \<open>
    1.99 -eval_drop_questionmarks;
   1.100 -\<close>
   1.101 -ML \<open>
   1.102 -val ctxt = Proof_Context.init_global @{theory};
   1.103 -val SOME t = TermC.parseNEW ctxt "eqr = drop_questionmarks eqr";
   1.104 -\<close>
   1.105 -ML \<open>
   1.106 -TermC.parseNEW ctxt "decomposedFunction p_p'''";
   1.107 -TermC.parseNEW ctxt "decomposedFunction";
   1.108 -\<close>
   1.109  
   1.110  (* current version, error outcommented *)
   1.111  (*ok
   1.112 @@ -245,28 +211,26 @@
   1.113            \<comment> \<open>([4], Frm), 3 / ((z - 1 / 2) * (z - -1 / 4)) = ?A / (z - 1 / 2) + ?B / (z - -1 / 4)\<close>
   1.114    eq = Take (eql = eqr);                  \<comment> \<open>([4], Res), 3 = ?A * (z - -1 / 4) + ?B * (z - 1 / 2)\<close>
   1.115    eq = (Try (Rewrite_Set ''equival_trans'' False)) eq; 
   1.116 -                                                  \<comment> \<open>eq = 3 = A * (z - -1 / 4) + B * (z - 1 / 2)\<close>
   1.117 -  eq = drop_questionmarks eq;                                                     \<comment> \<open>z1 = 1 / 2)\<close>
   1.118 +                                                 \<comment> \<open>eq = 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)\<close>
   1.119    z1 = rhs (NTH 1 L_L);                                                           \<comment> \<open>z2 = -1 / 4\<close>
   1.120 -  z2 = rhs (NTH 2 L_L);                  \<comment> \<open>([5], Frm), 3 = A * (z - -1 / 4) + B * (z - 1 / 2)\<close>
   1.121 -  eq_a = Take eq;                  \<comment> \<open>([5], Res), 3 = A * (1 / 2 - -1 / 4) + B * (1 / 2 - 1 / 2)\<close>
   1.122 -  eq_a = Substitute [zzz = z1] eq;                                \<comment> \<open>([6], Res), 3 = 3 * A / 4\<close>
   1.123 +  z2 = rhs (NTH 2 L_L);                   \<comment> \<open>([5], Frm), 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)\<close>
   1.124 +  eq_a = Take eq;                 \<comment> \<open>([5], Res), 3 = AA * (1 / 2 - -1 / 4) + BB * (1 / 2 - 1 / 2)\<close>
   1.125 +  eq_a = Substitute [zzz = z1] eq;                                \<comment> \<open>([6], Res), 3 = 3 * AA / 4\<close>
   1.126    eq_a = (Rewrite_Set ''norm_Rational'' False) eq_a;
   1.127 -\<comment> \<open>-----                                                    ([7], Pbl), solve (3 = 3 * A / 4, A)\<close>
   1.128 -                                                                          \<comment> \<open>([7], Res), [A = 4]\<close>
   1.129 +\<comment> \<open>-----                                                    ([7], Pbl), solve (3 = 3 * AA / 4, AA)\<close>
   1.130 +                                                                          \<comment> \<open>([7], Res), [AA = 4]\<close>
   1.131    sol_a = SubProblem (''Isac'', [''univariate'',''equation''], [''no_met''])
   1.132 -      [BOOL eq_a, REAL (A::real)] ;                                                     \<comment> \<open>a = 4\<close>
   1.133 -  a = rhs (NTH 1 sol_a);                   \<comment> \<open>([8], Frm), 3 = A * (z - -1 / 4) + B * (z - 1 / 2)\<close>
   1.134 -  eq_b = Take eq;                \<comment> \<open>([8], Res), 3 = A * (-1 / 4 - -1 / 4) + B * (-1 / 4 - 1 / 2)\<close>
   1.135 -  eq_b = Substitute [zzz = z2] eq_b;                               \<comment> \<open>([9], Res), 3 = -3 * B / 4\<close>
   1.136 -  eq_b = (Rewrite_Set ''norm_Rational'' False) eq_b;   \<comment> \<open>([10], Pbl), solve (3 = -3 * B / 4, B)\<close>
   1.137 -  sol_b = SubProblem (''Isac'',                                         \<comment> \<open>([10], Res), [B = -4]\<close>
   1.138 +      [BOOL eq_a, REAL (AA::real)] ;                                                     \<comment> \<open>a = 4\<close>
   1.139 +  a = rhs (NTH 1 sol_a);                   \<comment> \<open>([8], Frm), 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)\<close>
   1.140 +  eq_b = Take eq;                \<comment> \<open>([8], Res), 3 = AA * (-1 / 4 - -1 / 4) + BB * (-1 / 4 - 1 / 2)\<close>
   1.141 +  eq_b = Substitute [zzz = z2] eq_b;                               \<comment> \<open>([9], Res), 3 = -3 * BB / 4\<close>
   1.142 +  eq_b = (Rewrite_Set ''norm_Rational'' False) eq_b;   \<comment> \<open>([10], Pbl), solve (3 = -3 * BB / 4, BB)\<close>
   1.143 +  sol_b = SubProblem (''Isac'',                                         \<comment> \<open>([10], Res), [BB = -4]\<close>
   1.144        [''univariate'',''equation''], [''no_met''])
   1.145 -    [BOOL eq_b, REAL (B::real)];                                                       \<comment> \<open>b = -4\<close>
   1.146 -  b = rhs (NTH 1 sol_b);                             \<comment> \<open>eqr = A / (z - 1 / 2) + B / (z - -1 / 4)\<close>
   1.147 -  eqr = drop_questionmarks eqr;               \<comment> \<open>([11], Frm), A / (z - 1 / 2) + B / (z - -1 / 4)\<close>
   1.148 +    [BOOL eq_b, REAL (BB::real)];                                                       \<comment> \<open>b = -4\<close>
   1.149 +  b = rhs (NTH 1 sol_b);                             \<comment> \<open>eqr = AA / (z - 1 / 2) + BB / (z - -1 / 4)\<close>
   1.150    pbz = Take eqr;                            \<comment> \<open>([11], Res), 4 / (z - 1 / 2) + -4 / (z - -1 / 4)\<close>
   1.151 -  pbz = Substitute [A = a, B = b] pbz        \<comment> \<open>([], Res), 4 / (z - 1 / 2) + -4 / (z - -1 / 4)\<close>
   1.152 +  pbz = Substitute [AA = a, BB = b] pbz        \<comment> \<open>([], Res), 4 / (z - 1 / 2) + -4 / (z - -1 / 4)\<close>
   1.153  in pbz)                                                                                "
   1.154  *)
   1.155  setup \<open>KEStore_Elems.add_mets
   1.156 @@ -307,45 +271,43 @@
   1.157            "  (eq::bool) = Take (eql = eqr);                  " ^
   1.158            (*([4], Res), 3 = ?A * (z - -1 / 4) + ?B * (z - 1 / 2)*)
   1.159            "  eq = (Try (Rewrite_Set ''equival_trans'' False)) eq;" ^
   1.160 -          (*           eq = 3 = A * (z - -1 / 4) + B * (z - 1 / 2)*)
   1.161 -          "  eq = drop_questionmarks eq;                     " ^
   1.162 +          (*           eq = 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)*)
   1.163            (*           z1 = 1 / 2*)
   1.164            "  (z1::real) = (rhs (NTH 1 L_L));                 " ^
   1.165            (*           z2 = -1 / 4*)
   1.166            "  (z2::real) = (rhs (NTH 2 L_L));                 " ^
   1.167 -          (*([5], Frm), 3 = A * (z - -1 / 4) + B * (z - 1 / 2)*)
   1.168 +          (*([5], Frm), 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)*)
   1.169            "  (eq_a::bool) = Take eq;                         " ^
   1.170 -          (*([5], Res), 3 = A * (1 / 2 - -1 / 4) + B * (1 / 2 - 1 / 2)*)
   1.171 +          (*([5], Res), 3 = AA * (1 / 2 - -1 / 4) + BB * (1 / 2 - 1 / 2)*)
   1.172            "  eq_a = (Substitute [zzz = z1]) eq;              " ^
   1.173 -          (*([6], Res), 3 = 3 * A / 4*)
   1.174 +          (*([6], Res), 3 = 3 * AA / 4*)
   1.175            "  eq_a = (Rewrite_Set ''norm_Rational'' False) eq_a;  " ^
   1.176  
   1.177 -          (*([7], Pbl), solve (3 = 3 * A / 4, A)*)
   1.178 +          (*([7], Pbl), solve (3 = 3 * AA / 4, AA)*)
   1.179            "  (sol_a::bool list) =                            " ^
   1.180            "    (SubProblem (''Isac'', [''univariate'',''equation''], [''no_met''])   " ^
   1.181 -          (*([7], Res), [A = 4]*)
   1.182 -          "    [BOOL eq_a, REAL (A::real)]);                 " ^
   1.183 +          (*([7], Res), [AA = 4]*)
   1.184 +          "    [BOOL eq_a, REAL (AA::real)]);                 " ^
   1.185            (*           a = 4*)
   1.186            "  (a::real) = (rhs (NTH 1 sol_a));                " ^
   1.187 -          (*([8], Frm), 3 = A * (z - -1 / 4) + B * (z - 1 / 2)*)
   1.188 +          (*([8], Frm), 3 = AA * (z - -1 / 4) + BB * (z - 1 / 2)*)
   1.189            "  (eq_b::bool) = Take eq;                         " ^
   1.190 -          (*([8], Res), 3 = A * (-1 / 4 - -1 / 4) + B * (-1 / 4 - 1 / 2)*)
   1.191 +          (*([8], Res), 3 = AA * (-1 / 4 - -1 / 4) + BB * (-1 / 4 - 1 / 2)*)
   1.192            "  eq_b = (Substitute [zzz = z2]) eq_b;            " ^
   1.193 -          (*([9], Res), 3 = -3 * B / 4*)
   1.194 +          (*([9], Res), 3 = -3 * BB / 4*)
   1.195            "  eq_b = (Rewrite_Set ''norm_Rational'' False) eq_b;  " ^
   1.196 -          (*([10], Pbl), solve (3 = -3 * B / 4, B)*)
   1.197 +          (*([10], Pbl), solve (3 = -3 * BB / 4, BB)*)
   1.198            "  (sol_b::bool list) =                            " ^
   1.199            "    (SubProblem (''Isac'', [''univariate'',''equation''], [''no_met''])   " ^
   1.200 -          (*([10], Res), [B = -4]*)
   1.201 -          "    [BOOL eq_b, REAL (B::real)]);                 " ^
   1.202 +          (*([10], Res), [BB = -4]*)
   1.203 +          "    [BOOL eq_b, REAL (BB::real)]);                 " ^
   1.204            (*           b = -4*)
   1.205            "  (b::real) = (rhs (NTH 1 sol_b));                " ^
   1.206 -          (*           eqr = A / (z - 1 / 2) + B / (z - -1 / 4)*)
   1.207 -          "  eqr = drop_questionmarks eqr;                   " ^
   1.208 -          (*([11], Frm), A / (z - 1 / 2) + B / (z - -1 / 4)*)
   1.209 +          (*           eqr = AA / (z - 1 / 2) + BB / (z - -1 / 4)*)
   1.210 +          (*([11], Frm), AA / (z - 1 / 2) + BB / (z - -1 / 4)*)
   1.211            "  (pbz::real) = Take eqr;                         " ^
   1.212            (*([11], Res), 4 / (z - 1 / 2) + -4 / (z - -1 / 4)*)
   1.213 -          "  pbz = ((Substitute [A = a, B = b]) pbz)         " ^
   1.214 +          "  pbz = ((Substitute [AA = a, BB = b]) pbz)         " ^
   1.215            (*([], Res), 4 / (z - 1 / 2) + -4 / (z - -1 / 4)*)
   1.216            "in pbz)"
   1.217  )]