1.1 --- a/test/Tools/isac/Knowledge/polyeq-2.sml	Mon Apr 13 13:27:55 2020 +0200
     1.2 +++ b/test/Tools/isac/Knowledge/polyeq-2.sml	Mon Apr 13 15:31:23 2020 +0200
     1.3 @@ -287,14 +287,14 @@
     1.4  
     1.5  (*-6 * x + 5 * x ^ 2 = 0 : Rewrite_Inst (["(''bdv'',x)"],("d2_prescind1","")) --> x * (-6 + 5 * x) = 0*)
     1.6  t |> UnparseC.term; t |> atomty;
     1.7 -val thm = num_str @{thm d2_prescind1};
     1.8 +val thm = ThmC.numerals_to_Free @{thm d2_prescind1};
     1.9  thm |> Thm.prop_of |> UnparseC.term; thm |> Thm.prop_of |> atomty;
    1.10  val SOME (t', _) = rewrite_inst_ thy e_rew_ord Rule_Set.empty true subst thm t; UnparseC.term t';
    1.11  
    1.12  (*x * (-6 + 5 * x) = 0   : Rewrite_Inst (["(''bdv'',x)"],("d2_reduce_equation1","")) 
    1.13                                                                          --> x = 0 | -6 + 5 * x = 0*)
    1.14  t' |> UnparseC.term; t' |> atomty;
    1.15 -val thm = num_str @{thm d2_reduce_equation1};
    1.16 +val thm = ThmC.numerals_to_Free @{thm d2_reduce_equation1};
    1.17  thm |> Thm.prop_of |> UnparseC.term; thm |> Thm.prop_of |> atomty;
    1.18  val SOME (t'', _) = rewrite_inst_ thy e_rew_ord Rule_Set.empty true subst thm t'; UnparseC.term t'';
    1.19  (* NONE with d2_reduce_equation1:   "(bdv*(a +b*bdv)=0) = ((bdv=0)|(a+b*bdv=0))"