1.1 --- a/doc-src/TutorialI/Rules/Primes.thy Fri Nov 02 08:26:01 2007 +0100
1.2 +++ b/doc-src/TutorialI/Rules/Primes.thy Fri Nov 02 08:59:15 2007 +0100
1.3 @@ -4,11 +4,9 @@
1.4 (*Euclid's algorithm
1.5 This material now appears AFTER that of Forward.thy *)
1.6 theory Primes imports Main begin
1.7 -consts
1.8 - gcd :: "nat*nat \<Rightarrow> nat"
1.9
1.10 -recdef gcd "measure snd"
1.11 - "gcd (m, n) = (if n=0 then m else gcd(n, m mod n))"
1.12 +fun gcd :: "nat \<Rightarrow> nat \<Rightarrow> nat" where
1.13 + "gcd m n = (if n=0 then m else gcd n (m mod n))"
1.14
1.15
1.16 ML "Pretty.setmargin 64"
1.17 @@ -23,18 +21,18 @@
1.18
1.19 (*** Euclid's Algorithm ***)
1.20
1.21 -lemma gcd_0 [simp]: "gcd(m,0) = m"
1.22 +lemma gcd_0 [simp]: "gcd m 0 = m"
1.23 apply (simp);
1.24 done
1.25
1.26 -lemma gcd_non_0 [simp]: "0<n \<Longrightarrow> gcd(m,n) = gcd (n, m mod n)"
1.27 +lemma gcd_non_0 [simp]: "0<n \<Longrightarrow> gcd m n = gcd n (m mod n)"
1.28 apply (simp)
1.29 done;
1.30
1.31 declare gcd.simps [simp del];
1.32
1.33 (*gcd(m,n) divides m and n. The conjunctions don't seem provable separately*)
1.34 -lemma gcd_dvd_both: "(gcd(m,n) dvd m) \<and> (gcd(m,n) dvd n)"
1.35 +lemma gcd_dvd_both: "(gcd m n dvd m) \<and> (gcd m n dvd n)"
1.36 apply (induct_tac m n rule: gcd.induct)
1.37 --{* @{subgoals[display,indent=0,margin=65]} *}
1.38 apply (case_tac "n=0")
1.39 @@ -72,7 +70,7 @@
1.40 (*Maximality: for all m,n,k naturals,
1.41 if k divides m and k divides n then k divides gcd(m,n)*)
1.42 lemma gcd_greatest [rule_format]:
1.43 - "k dvd m \<longrightarrow> k dvd n \<longrightarrow> k dvd gcd(m,n)"
1.44 + "k dvd m \<longrightarrow> k dvd n \<longrightarrow> k dvd gcd m n"
1.45 apply (induct_tac m n rule: gcd.induct)
1.46 apply (case_tac "n=0")
1.47 txt{*subgoals after the case tac
1.48 @@ -87,7 +85,7 @@
1.49 *}
1.50
1.51 (*just checking the claim that case_tac "n" works too*)
1.52 -lemma "k dvd m \<longrightarrow> k dvd n \<longrightarrow> k dvd gcd(m,n)"
1.53 +lemma "k dvd m \<longrightarrow> k dvd n \<longrightarrow> k dvd gcd m n"
1.54 apply (induct_tac m n rule: gcd.induct)
1.55 apply (case_tac "n")
1.56 apply (simp_all add: dvd_mod)
1.57 @@ -95,7 +93,7 @@
1.58
1.59
1.60 theorem gcd_greatest_iff [iff]:
1.61 - "(k dvd gcd(m,n)) = (k dvd m \<and> k dvd n)"
1.62 + "(k dvd gcd m n) = (k dvd m \<and> k dvd n)"
1.63 by (blast intro!: gcd_greatest intro: dvd_trans)
1.64
1.65
1.66 @@ -107,7 +105,7 @@
1.67 (ALL d. d dvd m \<and> d dvd n \<longrightarrow> d dvd p)"
1.68
1.69 (*Function gcd yields the Greatest Common Divisor*)
1.70 -lemma is_gcd: "is_gcd (gcd(m,n)) m n"
1.71 +lemma is_gcd: "is_gcd (gcd m n) m n"
1.72 apply (simp add: is_gcd_def gcd_greatest);
1.73 done
1.74
1.75 @@ -133,12 +131,12 @@
1.76 \end{isabelle}
1.77 *};
1.78
1.79 -lemma gcd_assoc: "gcd(gcd(k,m),n) = gcd(k,gcd(m,n))"
1.80 +lemma gcd_assoc: "gcd (gcd k m) n = gcd k (gcd m n)"
1.81 apply (rule is_gcd_unique)
1.82 apply (rule is_gcd)
1.83 apply (simp add: is_gcd_def);
1.84 apply (blast intro: dvd_trans);
1.85 - done
1.86 + done
1.87
1.88 text{*
1.89 \begin{isabelle}
1.90 @@ -152,12 +150,12 @@
1.91 *}
1.92
1.93
1.94 -lemma gcd_dvd_gcd_mult: "gcd(m,n) dvd gcd(k*m, n)"
1.95 +lemma gcd_dvd_gcd_mult: "gcd m n dvd gcd (k*m) n"
1.96 apply (blast intro: dvd_trans);
1.97 done
1.98
1.99 (*This is half of the proof (by dvd_anti_sym) of*)
1.100 -lemma gcd_mult_cancel: "gcd(k,n) = 1 \<Longrightarrow> gcd(k*m, n) = gcd(m,n)"
1.101 +lemma gcd_mult_cancel: "gcd k n = 1 \<Longrightarrow> gcd (k*m) n = gcd m n"
1.102 oops
1.103
1.104 end